Experience the convenience of getting your questions answered at IDNLearn.com. Discover the information you need from our experienced professionals who provide accurate and reliable answers to all your questions.
Sagot :
3 number of roots exist for the polynomial function.
Step-by-step explanation:
As we know that the polynomial can only have exact number of roots as high as the degree of that polynomial is.
We can also prove it. Assume there is a polynomial
(x+2)(x+3) =0
Here the degree of the polynomial is 2 and the number of possible solutions are also 2. As it is evident that x is either equal to -2 or -3.
From the given condition,
(9x + 7)(4x + 1)(3x + 4)
we know that the degree of the polynomial is 3 because after expansion it becomes,
108x^3 + 255 x^2 +169x + 28 =0
Since, highest power of the variable is 3. Its degree is 3.
Therefore, possible number of roots that exist for the polynomial function are 3.
You can learn more about number of roots of polynomials from
https://brainly.com/question/10702726
#SPJ4
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for visiting IDNLearn.com. We’re here to provide clear and concise answers, so visit us again soon.