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according to the fundamental theorem of algebra, how many roots exist for the polynomial function? (9x 7)(4x 1)(3x 4)

Sagot :

3 number of roots exist for the polynomial function.

Step-by-step explanation:

As we know that the polynomial can only have exact number of roots as high as the degree of that polynomial is.

We can also prove it. Assume there is a polynomial

(x+2)(x+3) =0

Here the degree of the polynomial is 2 and the number of possible solutions are also 2. As it is evident that x is either equal to -2 or -3.

From the given condition,

(9x + 7)(4x + 1)(3x + 4)

we know that the degree of the polynomial is 3 because after expansion it becomes,

108x^3 + 255 x^2 +169x + 28 =0

Since, highest power of the variable is 3. Its degree is 3.

Therefore, possible number of roots that exist for the polynomial function are 3.

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