Answered

IDNLearn.com is your trusted platform for finding reliable answers. Discover trustworthy solutions to your questions quickly and accurately with help from our dedicated community of experts.

according to the fundamental theorem of algebra, how many roots exist for the polynomial function? (9x 7)(4x 1)(3x 4)

Sagot :

Maryamkincsemidn

3 number of roots exist for the polynomial function.

Step-by-step explanation:

As we know that the polynomial can only have exact number of roots as high as the degree of that polynomial is.

We can also prove it. Assume there is a polynomial

(x+2)(x+3) =0

Here the degree of the polynomial is 2 and the number of possible solutions are also 2. As it is evident that x is either equal to -2 or -3.

From the given condition,

(9x + 7)(4x + 1)(3x + 4)

we know that the degree of the polynomial is 3 because after expansion it becomes,

108x^3 + 255 x^2 +169x + 28 =0

Since, highest power of the variable is 3. Its degree is 3.

Therefore, possible number of roots that exist for the polynomial function are 3.

You can learn more about number of roots of polynomials from
https://brainly.com/question/10702726
#SPJ4

Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. IDNLearn.com provides the answers you need. Thank you for visiting, and see you next time for more valuable insights.