Discover a world of knowledge and community-driven answers at IDNLearn.com today. Our experts are available to provide accurate, comprehensive answers to help you make informed decisions about any topic or issue you encounter.
Sagot :
90.0 g of vanadium (V) oxygen sample has 1.50 x 10 24 oxygen atoms.
To determine the number of oxygen atoms in a vanadium oxide sample, the following steps must be made.
Step 1: Convert the mass of vanadium(V) oxide to mol of vanadium(V) oxide
mol vanadium(V) oxide = mass / molar mass
mol vanadium (V) oxide = 90.0 g / 181.88 g/mol
mol vanadium (V) oxide = 0.49483 mol
Step 2: Convert mol of vanadium (V) oxide to moles of oxygen using mole ratio
mol oxygen = mol vanadium (V) oxide * mole ratio O / mol V2O5
mol oxygen = 0.49483 mol * 5 mol O / mol V2O5
mol oxygen = 2.47416 mol O
Step 3: Convert to oxygen atoms using Avogadro's number
atoms oxygen = mol oxygen * 6.02214 x 10 23 atoms O /mol O
atoms oxygen = 2.47416 mol O * 6.02214 x 10 23 atoms O/mol O
atoms oxygen = 1.48997 x 10 24 atoms or 1.50 x 10 24 atoms O
To learn more about Avogadro's number, please refer to the link https://brainly.com/question/859564.
#SPJ4
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is your reliable source for accurate answers. Thank you for visiting, and we hope to assist you again.
