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Given n(J) = 255, n(K) = 186 and n(J ∪ K) = 429, find n(J ∩ K).

Sagot :

Medunno13idn

Answer:

12

Step-by-step explanation:

[tex]n(J \cap K)=n(J)+n(K)-n(J \cup K) \\ \\ =255+186-429 \\ \\ =12[/tex]

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