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a body’s weight varies inversely with the square of its distance from the center of the earth; if a chicken weighs 12 pounds when it is 5,000 miles from the earth’s center, how much will the chicken weigh when it is 10,000 miles from the earth’s center ?

Sagot :

The chicken will weigh 3 pounds when it is 10,000 miles from the earth's center.

There are two types of proportions.

1) Direct Proportion - shows the direct relationship between two quantities. It can be represented by the equation y = kx. As one quantity increases, the other quantity also increase.

2) Inverse Proportion - describes the indirect relationship between two quantities.  It can be represented by the equation y = k/x. As one quantity increases, the other quantity decreases.

According to the problem, a body’s weight varies inversely with the square of its distance from the center of the earth.

y = k/x

let y = a body's weight

x = square of its distance from the center of the earth

Solving for the proportionality constant, k.

y = k/x

12 = k / (5000^2)

k = 12 x 25, 000, 000

k = 300, 000, 000

The equation for the relationship in the problem can now be represented by:

y = 300,000,000/x

where

y = a body's weight

x = square of its distance from the center of the earth

Evaluating the new equation where x = square of 10,000:

y = 300,000,000/x

y = 300,000,00/(100,000,000)

y = 3

Hence, the chicken will weigh 3 pounds when it is 10,000 miles from the earth's center.

To know more about proportions: https://brainly.com/question/1266676

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