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The two values that serves as the root of the equation are -1-√7 and -1+√7
Given the quadratic equation below;
X² + 2X (-6) = 0
x^2 + 2x - 6 = 0
Using the general formula
x = -2±√2²-4(1)(-6)/2(1)
x = -2±√4+24/2
x = -2±√28/2
x = -2±2√7/2
x = -1±√7
Hence the two values that serves as the root of the equation are -1-√7 and -1+√7
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