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How would you prepare 10mL of a 0.25% m/V HCI solution if 1% m/V HCI was available? How much 1% m/V HCI is needed? How much distilled water is used?

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We need to add 7.5 mL of distilled water to the 1% m/V HCI solution available.

What is the volume needed?

The percent concentration is one of the common units of concentration that could be used to describe the amount of substance. Let us now try to obtain the volume needed.

Given that;

C1V1=C2V2

C1 = initial concentration

V1 = Volume of the stock solution

C2 = final concentration

V2 = volume of the new solution

Thus;

V1 = C2V2/C1

V1 = 0.25 * 10/1

= 2.5 mL

Hence, the volume of distilled water needed =  10mL - 2.5 mL

= 7.5 mL

Thus, we need to add 7.5 mL of distilled water to the 1% m/V HCI solution available.

Learn more about concentration:https://brainly.com/question/10725862

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