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p(x) = x³ - x² + x + 1
i ) p(-1) = (-1)³ - ( -1 )² + ( -1 ) + 1
= -1 - 1 - 1 + 1
= -2
ii ) p( 1 ) = 1³ - 1² + 1 + 1
= 1 - 1 + 1 + 1
= 2
Now ,
[ p(-1) + p(1) ]/2
= [ -2 + 2 ]/2
= 0
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