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2. A farmer moves along the boundary of a square field side 10m in 40 sec. What will be the magnitude of displacement of the farmer at the end of 2 min 20 seconds from his initial position.

Sagot :

Answer:

The farmer is moving at 10 m / 40 s = .4 m/s

2 min 20 sec = 140 sec

The farmer will have moved 140 * .4 = 56 m

To cover the x-axis twice he will have moved x = 10

56 - 50 = 6 m   and he will have moved a distance of 6 on the y-axis

S = (10^2 + 6^2)^1/2 = 11.7 m from the origin

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