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Q21 90g of glucose is dissolved in water. The glucose solution is fermented. C6H12O62CO₂ + 2C₂H₂OH glucose, M, = 180 After the fermentation finishes, 6.8g of ethanol is obtained from the solution. What is the percentage yield of ethanol? A 7.4 B 7.6 C 14.8 ethanol, M, = 46 D 29.6​

Sagot :

The correct answer is 14.8%.

The given reaction,

C_6H_12O_6 ----> 2CO₂ + 2C₂H₂OH

A key idea in chemistry is stoichiometry, which determines the quantity of reactants or products in a chemical reaction and aids in understanding different reactions and the proportions in which they might take place. A combination of two Greek terms is stoichiometry. Stoicheion, which denotes an element, and metron, which denotes a unit of measurement

mole= mass/mole mass

=90g/180g/mol

=0.5mol

According to stoichiometry

1 mol glucose = 2 mol ethanol

0.5 mol C_6H_12O_6 = 1 mole ethanol

mass of ethanol = 1 mole ×46 g/ mol

Theoretical yield = 46 g

percentage = actual yield / theoretical yield × 100

=6.8 g / 46 g × 100 = 14.78% =14.8%

To learn more about percentage yield refer the link:

https://brainly.com/question/15443303

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