Hello and Good Morning/Afternoon:
Let's take this problem step-by-step:
First Question:
[tex]\text{Copy the equation}\\\hookrightarrow \frac{xy^4}{x^3y^2} \\\\\text{Exponents with common bases when dividing from each other}\\\hookrightarrow \text{the power of the denominator can be subtracted from the power of the numerator}\\ \text{ --- } \dfrac{xy^4}{x^3y^2} =\dfrac{x}{x^3}*\dfrac{y^4}{y^2}=x^{1-3}*y^{4-2}=x^{-2}*y^{2} =\dfrac{y^2}{x^2}[/tex]
Second Question:
[tex]\hookrightarrow\text{simply start from the most inner calculation before going out}[/tex]
[tex]\text{---}-(-x)^3= -1 *(-1 * x)^3=-1*(-1)^3*x^3=-1*-1*x^3=x^3[/tex]
Answer:
Hope that helps!
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