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At the end of a race a runner decelerates from a velocity of 9.00 m/s at a rate of 0.300 m/s2.
(a) How far does she travel in the next 15.0 s?

(b) What is her final velocity?

Sagot :

(a)In the next 15.0s, she traveled 101.250 m.

(b) 4.50 m/s is the runner's final speed.

Given:- initial velocity = 9m/s , deacceleration = 0.3 m/s2

distana(d), she moves in time (t)=15 s,

and we must determine this using the second equation of motion.

S = ut + 1/2 at2,

where s = the distance

u = initial velocity

t = time

a=-d = 0.300m/s

t=15.0

By putting all values in the formula above,

we have

d = (9.00)x(15.0)-1/2 (0.300) (15.0)²

d= 101.250 m.

In the next 15.0s, she traveled 101.250 m.

final speed  (v) =?

from 1 Equation of Motion : v = u+at.

To solve, v=?

u=9.00 m/s

a= -d= 0.300 m/s²

t=15.0

v=u+at

v= 9 - 0.300 X15.0

= 4.50 m/s

4.50 m/s is the runner's final speed.

Learn more about Equation of Motion here:

https://brainly.com/question/15080570

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