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Answer:
There are no values of x that make this equation true.
Step-by-step explanation:
We know h(x)=[tex]\sqrt{x-3} +5[/tex]
So lets substitute h(x) for 3
3=[tex]\sqrt{x-3}+5[/tex]
We are going to then subtract 5 from each side leaving us with
-2=[tex]\sqrt{x-3}[/tex]
We then need to get rid of the square root, so we will square both sides. which gives us
4=x-3
We then need to subtract 3 from both sides which leaves us with
x=1
However, when you substitute 1 for x into the original equation, you get
h(x)=[tex]\sqrt{-2}+5[/tex]
Which is not equal to 3
Therefore, there are no values of x that make this equation true.