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What is concentration of N2O5 in the following first order reaction in which the rate is 2.4*10^-5 mole/L and rate constant is 3 * 10 ^ - 5 * S ^ - 1 ?​

Sagot :

0.8mole/L is concentration of N2O5.

As the reaction is first order ,

so the order with respect to N2O5 is 1.

general,

Rate of equation is written as

rate = k [N2O5]^1

k is the rate constant = 3 * 10 ^ - 5 * S ^ - 1

rate = 2.4*10^-5 mole/L

N2O5 is concentration term

2.4*10^-5 mole/L  = 3 * 10 ^ - 5 * S ^ - 1 [  N2O5]

 N2O5 = [0.8 mole/L]

=0.8mole/L

Learn more about N2O5 here:

https://brainly.com/question/19100869

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