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Write the equation of a line perpendicular to the line: y = 2x - 1 that goes through the point (-8, -5).
Write your answer in slope- intercept form, using reduced fractions for the slope and intercept


Sagot :

The equation of a line perpendicular to the line is y = (-1/2)x - 9

Slope of the line perpendicular to y = 2x - 1, m =-1/2;

Therefore, equation of line perpendicular to given line in slope- intercept form is; y = (-1/2) x + c;

This line passes through (-8, -5); therefore;

-5 = (-1/2)(-8) + c;

c = -9;

Therefore, equation of required line is y = (-1/2)x - 9;

Perpendicular lines are two non-vertical lines in the same plane that intersect at a right angle. Horizontal and vertical lines are perpendicular to one other, forming the coordinate plane's axes. Negative reciprocals are the slopes of two perpendicular lines.

Vertical and horizontal lines are parallel to each other. In this scenario, the slope of the perpendicular line is equal to the slope of a horizontal line, which is 0. The slope of the parallel line is 0 while the slope of the perpendicular line is unknown.

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