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The number of nails in each box is: 1300, 1400, 600, 1200, and 500
Given 5000 nails in five boxes.
Let X denote the universal set.
Then n(X) = 5000.
Let A denote the first box,
B denote the second box,
C denote the third box,
D denote the fourth box, and
E denotes the fifth box.
The first and second boxes have 2700 nails altogether.
⇒n(A ∪ B) = 2700
The second and third boxes have 2000 nails altogether.
⇒n(B ∪ C) = 2000
The third and fourth boxes have 1800 nails altogether.
⇒n(C ∪ D) = 1800
The fourth and fifth boxes have 1700 nails altogether.
⇒n(D ∪ E) = 1700
We need to find out how many nails are there in each box.
That is to find out: n(A), n(B), n(C), n(D), and n(E).
Note that all these five sets are disjoint. This means that the intersection is empty.
n(A ∪ B ∪ C ∪ D) = n(A ∪ B) + n(C ∪ D) = 2700 + 1800 = 4500
n(E) = n(X) - n(A ∪ B ∪ C ∪ D) = 5000 - 4500 = 500
n(D) = n(D ∪ E) - n(E) = 1700 - 500 = 1200
n(C) = n(C ∪ D) - n(D) = 1800 - 1200 = 600
n(B) = n(B U C) - n(C) = 2000 - 600 = 1400
n(A) = n(A U B) - n(B) = 2700 - 1400 = 1300
Therefore, the number of nails in each box is 1300, 1400, 600, 1200, and 500.
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