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How many moles of Ne are contained in a 5.00 L tank at 155°C and 2.80 atm?

Sagot :

There will be 0.39 moles

Take a look at the He gas in the tank:

P = 2.80 atm, or pressure

Volume = 5.00 liters.

T = (273 + 155) is the temperature. K = 428 K

R = 0.08206 L atm/L of gas (mol K)

Charle's law, Boyle's law, and Gay-Lussac law are the three gas laws that make up the combined gas law, commonly referred to as a general gas equation. For a certain amount of gas, the law illustrates the relationship between temperature, volume, and pressure.

Gas law PV = nRT

So, n = PV/. (RT)

He gasses number = 2.80 x 5.00 / (0.08206 x 428) mol equals 0.39 mol.

Learn more about Gas law here-

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