Explore IDNLearn.com to discover insightful answers from experts and enthusiasts alike. Get accurate answers to your questions from our community of experts who are always ready to provide timely and relevant solutions.
Number of train rides to make the frequent-rider pass a better deal than standard train tickets is 26 or more rides.
As given,
Cost of standard train ticket = 3 per ride
Price of frequent rider pass= 18.75 each month
Cost of ticket using rider pass = 2.25 per ride
let x be the number of rides
Equation:
18.75 + 2.25x < 3x
⇒ 0.75x > 18.75
⇒ x > 25
Therefore, number of train rides to frequent-rider pass a better deal than standard train tickets is 26 or more rides.
Learn more about numbers here
brainly.com/question/17429689
#SPJ4