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Sometimes we ask you to enter an equation and not just an expression. find an equation of a line that has slope 8 and passes through the point (3, 11).

Sagot :

The equation of the straight line is 8x - y = 85.

It is given that the slope of the line is 8 and passes through the point (3,11).

We have to find the equation of the line.

We know that,

Equation of a line is :-

[tex]y -y_1 = m (x - x_1)[/tex]

Where,

x and y are variables

m is the slope of the line

[tex](x_1,y_1)[/tex] are the coordinates of the point that passes through the line.

Here,

[tex](x_1,y_1)[/tex] = (3,11)

m = 8

Hence,

Equation of the line = y - 3 = 8(x - 11)

y - 3 = 8x - 88

8x - y = -3 + 88

8x - y = 85

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