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Sagot :
The point at which Leila should stop to take break is (6.25 , 3.75)
Given P(10 , 3) and R (0 , 4)
The ratio is 3:5
Let the break point be point B.
The formula is : (n(x₁) ₊ m(x₂)/ m₊n , n(y₁) ₊ m(y₂)/ m₊n)
P(10,3) = (x₁ , y₁)
R(0,4) = (x₂ , y₂)
m:n = 3:5
B = (5(10) ₊ 3(0)/3₊5 , 5(3) ₊ 3(4)/3₊5)
B = (50₊0/8 , 15₊12/8)
B = (50/8 , 27/8)
B = (6.25 , 3.75)
Hence Leila should stop at point (6.25 , 3.75) for her break.
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