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Halla tres enteros pares consecutivos tales que 6 veces el primer entero sea 26 más que la suma del segundo y tercer enteros.

Sagot :

The consecutive even integers are 8, 10 and 12.

How to calculate the value?

Let the integers be x, x + 2, and x + 4.

Therefore, the equation will be:

6(x) = x + 2 + x + 4 + 26

6x = 2x + 32

Collect like term

6x - 2x = 32

4x = 32

Divide

x = 32/4.

x = 8

The numbers are 8, 10 and 12.

Learn more about integers on:

brainly.com/question/17695139

#SPJ1

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