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1. If you know that limx→−1 f(x)=−3 and limx→0 g(x)=3, then evaluate the following limit:
limx→0 f(x−1)g(x)=
2. If you know that limx→4 f(x)=3 and limx→0 g(x)=−5, then evaluate the following limit:
limx→0 f(x+4)+g(x)=

Sagot :

Applying it's properties, the limits of the functions are given as follows:

1. 9.

2. -2.

What is a limit?

A limit is given by the value of function f(x) as x tends to a value. Algebraically, for continuous functions, we have that:

[tex]\lim_{x \rightarrow a} f(x) = f(a)[/tex].

Hence, applying the property above, for item 1, we have that:

limx→0 f(x−1)g(x) = f(0 - 1)g(0) = f(-1)g(0) = -3 x 3 = 9.

For item 2, we have that:

limx→0 f(x+4)+g(x) = limx→4 f(x) + limx→0 g(x) = 3 - 5 = -2.

More can be learned about limits at https://brainly.com/question/26270080

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