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Find the area of the smaller sector.
Round to the nearest tenth.
77⁰
10.7 th
Area = [? ]in²


Find The Area Of The Smaller Sector Round To The Nearest Tenth 77 107 Th Area In class=

Sagot :

The Area is 81 [tex]in^{2}[/tex]. Lets see the solution.

Given:

π=[tex]\frac{22}{7}[/tex]

r=10.7

∅ = 77°

Solution :

= [tex]\frac{∅}{360°}[/tex]×π[tex]r^{2}[/tex]

=[tex]\frac{77}{360}[/tex]×[tex]\frac{22}{7}[/tex]×[tex]11^{2}[/tex]

= [tex]\frac{11}{360}[/tex]×22×121

=[tex]\frac{11^{2} }{180}[/tex]

Area =[tex]81in^{2}[/tex]

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