Find solutions to your problems with the help of IDNLearn.com's expert community. Join our interactive community and get comprehensive, reliable answers to all your questions.
Sagot :
Taking into account the reaction stoichiometry, the mass of ammonia formed is 34 grams.
Reaction stoichiometry
In first place, the balanced reaction is:
N₂ + 3 H₂ → 2 NH₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- N₂: 1 mole
- H₂: 3 moles
- NH₃: 2 moles
The molar mass of the compounds is:
- N₂: 28 g/mole
- H₂: 2 g/mole
- NH₃: 17 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- N₂: 1 mole ×28 g/mole= 28 grams
- H₂: 3 moles ×2 g/mole= 6 grams
- NH₃: 2 moles ×17 g/mole= 34 grams
Mass of ammonia formed
In this case, by reaction stoichiometry, a 28.0 g sample of nitrogen gas combines completely with 6.0 g of hydrogen gas. So, the mass of ammonia formed is 34 grams.
In summary, by reaction stoichiometry, the mass of ammonia formed is 34 grams.
Learn more about the reaction stoichiometry:
brainly.com/question/24741074
brainly.com/question/24653699
#SPJ1
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Discover the answers you need at IDNLearn.com. Thanks for visiting, and come back soon for more valuable insights.