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A person's systolic blood pressure, which is measured in millimeters of mercury (mm Hg), depends on a person's age, in years. The equation
p=0.007y^2-0.003y+122
gives a person's blood pressure, p,at the age y year

A.) Find the systolic pressure, to the nearest tenth of a millimeter, for a person of age 41 years.

Sagot :

The systolic pressure, to the nearest tenth of a millimeter, for a person of age 41 years is; 133.6 mm Hg

How to solve problems using quadratic equations?

We are given the equation that gives a person's blood pressure, p at the age y year is;

p = 0.007y² - 0.003y + 122

To find the systolic pressure for a person of age 41 years, just plug in y = 41 into the given quadratic equation to get;

p(41) = 0.007(41)² - 0.003(41) + 122

p(41) = 11.767 - 0.123 + 122

p(41) = 133.6

Thus, the systolic pressure, to the nearest tenth of a millimeter, for a person of age 41 years is; 133.6

Read more about Quadratic Equations at; https://brainly.com/question/1214333

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