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Evaluate the function.
ƒ(x) = −x² − 4x – 12
Find ƒ(-7)


Sagot :

Given ~

[tex] \tt \: f(x) = - {x}^{2} - 4x - 12[/tex]

[tex] \: [/tex]

put the value of x = -7 in given function ~

[tex] \tt \: f( - 7) = - ( { - 7})^{2} - 4( - 7)- 12[/tex]

[tex] \: [/tex]

[tex] \tt \: f( - 7) = - 49 +28 - 12[/tex]

[tex] \: [/tex]

[tex]\tt \: f( - 7) = - 21 - 12[/tex]

[tex] \: [/tex]

[tex] \underline{ \boxed{ \tt \red{ f( - 7) = -33}}}{ \green ✓}[/tex]

[tex] \: [/tex]

hope helps ~