IDNLearn.com makes it easy to find the right answers to your questions. Get step-by-step guidance for all your technical questions from our dedicated community members.
Sagot :
[tex]6[/tex][tex]x^{12}[/tex][tex]y^{11}[/tex][tex]z^{19}[/tex][tex]\sqrt{5xyz}[/tex]
How do you define the square root of a number?
In mathematics, a square root of a number x is a number y such that y^2 = x; in other words, a number y whose square (the result of multiplying the number by itself, or y ⋅ y) is x. For example, 4 and −4 are square roots of 16, because 42 = (−4)2 = 16.
[tex]\sqrt{180x^{25 } y^{23} z^{39}[/tex]
[tex]180 = 2*2*3*3*5\\x^{25} = x*x*x........*x 25 times\\y^{23}= y*y*y.........*y 23 times\\ z^{39} = z*z*z........*z 39 times[/tex]
we have
square terms comes out
x is 25 times so we can write x as [tex](x^{12})^{2}[/tex] [tex]*[/tex][tex]x[/tex] therefore [tex]x^{12}[/tex] comes out and only left inside is x
similarly [tex](y^{11})^{2}[/tex] [tex]*y[/tex] therefore [tex]y^{11}[/tex] comes out and only left inside is y
[tex](z^{19})^{2} *z[/tex] therefore [tex]z^{19}[/tex] comes out and left inside is z
then the expression become
[tex]6[/tex][tex]x^{12}[/tex][tex]y^{11}[/tex][tex]z^{19}[/tex][tex]\sqrt{5xyz}[/tex]
learn more about of expression here
https://brainly.com/question/17579585
$SPJ9
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For precise answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.
