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On a number line, point A is located at 1, point C is located at −4, and point B lies between points A and C. What is the location of B such that the ratio of CB:BA is 3:1?

Sagot :

The location of point B on the given number line is; -0.5

How to partition a line segment?

We are given that on a number line AC;

Location of Point A = 1

Location of point C = -4

Now, we are told that B divides line AC in the ratio CB:BA = 3:1.

Thus;

CB = 3/4 of the length of AC

BA = 1/4 the length of AC

CB = 3/4 * 6 = 4.5

BA = 1/4 * 6 = 1.5

Thus, location of point B is; -4 + 4.5 = -0.5

Read more about Line Segment Partition at; https://brainly.com/question/17374569

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