Answered

IDNLearn.com provides a collaborative platform for sharing and gaining knowledge. Find reliable solutions to your questions quickly and accurately with help from our dedicated community of experts.

Ph=4.390 write the henderson-hasselbalch equation for a propanoic acid solution (ch3ch2co2h, pka=4.874). 4.390

Sagot :

Ughiwishloloidn

Answer:

a) [A⁻]/[HA] = 0.227b) [A⁻]/[HA] = 0.991c) [A⁻]/[HA] = 2.667Explanation:In the Henderson-Hasselbalch equation, HA stands from an acid an A⁻ stands from its conjugate base, as follows:CH₃CH₂CO₂H = HACH₃CH₂CO₂⁻ = A⁻pH = pka + Log [A⁻]/[HA]pH = 4.874 + Log[CH₃CH₂CO₂⁻]/[CH₃CH₂CO₂H](a) 4.23 = 4.874 + Log [A⁻]/[HA]-0.644 = Log [A⁻]/[HA] = [A⁻]/[HA]0.227 = [A⁻]/[HA](b) 4.87 = 4.874 + Log [A⁻]/[HA]-0.004 = Log [A⁻]/[HA] = [A⁻]/[HA]0.991 = [A⁻]/[HA](c) 5.30 = 4.874 + Log [A⁻]/[HA]0.426 = Log [A⁻]/[HA] = [A⁻]/[HA]2.667 = [A⁻]/[HA]

Explanation:

We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. Find reliable answers at IDNLearn.com. Thanks for stopping by, and come back for more trustworthy solutions.