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Sagot :
The kinetic energy of the helium nucleus will be 4.98 x 10⁻¹³ J
Kinetic energy can be define as , that it is a form of energy that an object or a particle is cause of its motion. Its unit is joule i.e. j & it is given as,
K.E. = 1/2 mv²
where , m is mass of the particle and v is the velocity of the particle .
Energy can be expressed as, the ability to perform work. Energy can neither be created nor destroyed, but it can only be transformed from one form to another. The unit of energy is joule .
Mass of helium nucleus = m = 6.64 x 10⁻²⁷ kg
Speed of light = c = 3 x 10⁸ m/s
Speed of light at 5.00% = c = 5.00/100x 3 x 10⁸ m/s = 1.5 x 10⁷ m/s
The kinetic energy of the helium nucleus can be given as ,
K.E = ¹/₂mc²
K.E = ¹/₂ x (6.64 x 10⁻²⁷) x (1. 5 x 10⁷)²
K.E = 4.98 x 10⁻¹³ J
Therefore, the kinetic energy of the helium nucleus is 4.98 x 10⁻¹³ J
To know more about kinetic energy
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