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What is the minimum diameter of a steel wire if it is to support a mass of 80 kg? the elastic limit of steel is 5.0*10^8 pa

Sagot :

The minimum diameter of a steel wire is 1.41mm

STRESS : The restoring force per unit area. unit of stress is N/m²

     It is denoted by σ

      σ = F/ A

Where σ = stress

F = force

A = area

force = ma

Area of a steel wire is πr²

2r = d

so area becomes

π(d/2)² =πd²/4

here , mass = 80kg

elastic limit = 5.0×10⁸kg

using these values

σ = mg/ πr²

5×10⁸ = 80×10³ × 9.8/ π*d²/4

π *d²/4 = 784 ×10³ /  5×10⁸

           = 156.8 ×10⁻⁵

   d² = 19.9×10⁻⁵

   d = 1.41 mm

The minimum diameter of a steel wire is 1.41mm

To know more about the elasticity :

https://brainly.com/question/28447665

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