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Sagot :
The Mole fraction of Water in this solution is 0.34
We know that,
Mole Fraction of Water = No. of moles of Water / Total number of moles of the solution
No. of moles = Mass / Molar mass
Given that,
Mass of Water = 11g
Mass of Acetic acid = 72g
Molar mass of Water = 18.015 g/mol
Molar mass of Acetic acid = 60.052 g/mol
No. of moles of Water= 11 / 18.015= 0.611 moles
No. of moles of Acetic acid = 72 / 60.052= 1.199 moles
Total no. of moles = 0.611+ 1.199 = 1.81 moles
Mole fraction of chloroform = 0.611 / 1.81 = 0.338
In a solution containing at least 2 components, the number of moles of one component divided by total number of moles in that solution is called Mole fraction.
Therefore, the Mole fraction of Water in this solution is 0.34
To know more about Mole fraction
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