Discover new perspectives and gain insights with IDNLearn.com's diverse answers. Get accurate answers to your questions from our community of experts who are always ready to provide timely and relevant solutions.

If the initial concentration of so2cl2so2cl2 is 0.150 mm , what is the concentration of so2cl2so2cl2 after 190 ss ? [so2cl2]t[so2cl2]t = 1.13 mm submitprevious answersrequest answer

Sagot :

Use integrated first order rate law, which give you the concentration of reactant sulfuryl chloride as function of time t:  

ln[SO₂Cl₂] = ln[SO₂Cl₂]₀ - k∙t  

([SO₂Cl₂]₀ i the initial concentration and k is the rate constant)  

=>  [SO₂Cl₂] = e^(ln[SO₂Cl₂]₀ - k∙t) = e^(ln[SO₂Cl₂]₀) ∙ e^( - k∙t)  

= [SO₂Cl₂]₀ ∙e^( - k∙t)  

The decomposition of SO₂Cl₂ follows the reaction equation  

SO₂Cl₂ → SO₂ + Cl₂  

So per mole of sulfuryl chloride disappeared one mole of sulfur dioxide is formed. Hence the changes in concentrations of these compounds are related as:  

-∆[SO₂Cl₂] = ∆{SO₂]  <=>  [SO₂Cl₂]₀ - [SO₂Cl₂] = [SO₂] - [SO₂]₀  

Assuming there was initially no sulfur dioxide you get for its concentration:  

[SO₂] = [SO₂Cl₂]₀ - [SO₂Cl₂]  

= [SO₂Cl₂]₀ - [SO₂Cl₂]₀ ∙e^( - k∙t)  

= [SO₂Cl₂]₀ ∙(1 - e^( - k∙t))  

after 210s starting with 0.150M of [SO₂Cl₂]  

[SO₂]= 0.150M ∙(1 - e^( - 1.48×10⁻⁴s⁻¹k ∙ 240s) =

Learn more about concentration here:

https://brainly.com/question/10725862

#SPJ4