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Sagot :
Mass of kool aid required is 3.42g to make 0.2 mole solution 1 liter
by the formula of molarity we know that molarity = mole/liter
We can enter those values into the equation to determine the necessary number of moles because we know that we want a 0.1Mole solution in 100 mL so by substituting the values 1/ 0.1= 0.01 moles.
We now know that there are 0.01 moles of Kool-Aid powder. Additionally, we are aware that this powder's chemical composition is c12 h22o11
By multiplying the atomic weight from the periodic table by the quantity of atoms in the compound, we may determine the molar weight of this powder. Let's calculate the powder's molar weight:
Find the carbon atomic weight
12 X 12 =144g
Then we have 22 H's, each having an atomic weight of 1.008g
22 X 11= 22g
And finally there are 11 O's, each with an atomic weight of 16g
16 X11 =176g
by adding the atomic weight of atoms 342.19g
now by finding the grams of kool compound 342.19 X 0.01mol = 3.42g.
now we know that we need 0.01 moles of the powder, and we need 3.42g of the powder to make the desired solution
To learn more about mole:
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