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On mars, the acceleration due to gravity is 3.77 m/s2. how far would a 47 g rock fall from rest in 6.5 s if the only force acting on it was the gravitational force due to mars?

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On mars the rock that fall from rest in 6.5 s with an acceleration due to gravity of 3.77 m/s² would far a distance of: 79.64125 m

The free fall formula and the procedure we will use is:

h = (g * t²)/2

Where:

  • g = acceleration due to gravity
  • t = time
  • h = height traveled

Information of the problem:

  • g = 3.77 m/s²
  • t = 6.5 s
  • h =?

Applying final height formula we get:

h = (g * t²)/2

h = (3.77 m/s² * (6.5 s)²)/2

h = (3.77 m/s² * 42.25 s²)/2

h = 159.2525 m/2

h = 79.64125 m

What is free fall?

It is when the object or mobile falls from a height (h) with a positive acceleration equal to the gravity, describing a vertical rectilinear travel.

Learn more about free fall at brainly.com/question/11257529

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