IDNLearn.com is the perfect place to get answers, share knowledge, and learn new things. Join our knowledgeable community and get detailed, reliable answers to all your questions.
Sagot :
The correct answer for percentage of the compound is left after 3.32 minutes is 55 % .
We use the formula A(t) = A0e-kt for decomposition, where A0 is the initial amount of decomposed substance at t = 0, k is the decay constant, t is the time elapsed, and A(t) is the amount after time t.
The percentage of decomposed compound left after a time t is, [A(t)], divided the the initial amount, [A0], time 100, or A/A0*100:
A = A0e-kt
A/A0 = e^- 0.00586t, [k = 0.00299, divide both sides by A0]
A/Ao = e^(-0.00299*199), [t = 3.32 min*(60 sec/ 1 min) =199 sec]
A/A0 = . 0.551= 55%, (* 100, rounded)
The Arrhenius equation is k = Ae(-Ea/kT), where A is the frequency or pre-exponential factor and e(-Ea/RT) is the fraction of collisions at temperature T that have enough energy to overcome the activation barrier (i.e., have energy greater than or equal to the activation energy Ea).
Learn more about percentage decomposition here :-
https://brainly.com/question/21438582
#SPJ4
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com is dedicated to providing accurate answers. Thank you for visiting, and see you next time for more solutions.
