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What is the probability of spinning B on the first spinner and an even number on the second spinner?

What Is The Probability Of Spinning B On The First Spinner And An Even Number On The Second Spinner class=

Sagot :

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Answer:

[tex]\frac{2}{15}[/tex]

Step-by-step explanation:

On the first spinner, there are 3 possible outcomes. Of those 3 outcomes, only one is what we're looking for (Landing on B). This means that the chance to land on B on the first spinner is [tex]\frac{1}{3}[/tex].

For the second spinner, There a 5 possible outcomes, and 2 even numbers on the spinner, meaning the chance to land on an even number is [tex]\frac{2}{5}[/tex].

Since these are independent events, we can simply multiply these numbers together and get [tex]\frac{1}{3}*\frac{2}{5}=\frac{2}{15}[/tex].

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