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The temperature when the pressure in the thermometer is 6.00 atm is T2= 30.933 K
As specified by the IUPAC since 1982, one mole of an ideal gas has a volume of 22.710947(13) litres at standard conditions of temperature and pressure (273.15 K and precisely 105 Pa).
continuous volume,
Constant = PT
P equals pressure.
temperature, or T
Then
TTtri=PPtri
PPtriTtr = 273.16 SoT
Water's triple point temperature is i.
We have provided
P =0.0630 atm
T =348 K
T = 273.16 is the triple point value.
P/Ptri
Ptri = 273.16 then.
PT= 273.16 × 0.0630/348
Ptri = 0.0494 atm.
P =0.00560 atm
Ideal gas is present here at constant volume.
Thus, PT = Constant
P2T2=P1T1
T2 = P2
T1P1=0.00560×348
=0.0630
T2= 30.933 K
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