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The molal concentration of the solution is 5.38 M.
The molal concentration of sulphuric acid = 6.80 m
The density of the solution = 1.318 g/ml
Mass of the sulphuric acid in the solution is,
[tex] = 6.80 \times 9.80[/tex]
[tex] =666.4 \: g[/tex]
The mass of sulphuric acid present in the solution is 666.4 g.
Let the mass of the solvent in which sulphuric acid is dissolved be 1000 grams.
So the total mass of the solution is,
= Mass of solvent + Mass of sulphuric acid
[tex] = 666.4 \: + \: 1000[/tex]
[tex] = 1666.4 \: g[/tex]
The total volume of the solution is,
[tex] = \frac{1666.4 \times 1}{1.318 \times 1000} [/tex]
[tex] = 1.264 \: L[/tex]
The volume of the solution is 1.264 liters.
The molal concentration of this solution is,
[tex] = \frac{6.80}{1.264} [/tex]
[tex] = 5.38 \: M[/tex]
Therefore, the molal concentration of the solution is 5.38 M.
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