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Consider the reaction, 2 d(g) 3 e(g) f(g) => 2 g(g) h(g) when d is decreasing at 0.69 mol/ls, how quickly is f decreasing? give your answer to 3 decimal places.

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The compound f is increasing at the rate of 0.46 mol per second.

The number of moles of a compound is defined as the mass of the compound divided by its molecular mass. The SI unit of the number of moles is mol. The number of moles is represented by the symbol 'n'.

[tex]Number \: of \: moles = \frac{ Mass}{ Molecular \: mass}[/tex]

[tex]n = \frac{m}{M} [/tex]

The balanced equation for the reaction is,

2 d (g) + 3 e (g) + f (g) => 2 g (g) + h (g)

In the reaction, 3 moles of compound e are consumed to give 2 moles of compound g.

For 1 mole of compound e consumed to form =

[tex] \frac{2}{3} \: moles \: of \: g \: formed.[/tex]

The compound e is decreasing at the of = 0.69 mol/s

So, the rate at which g is increasing is,

[tex] = \frac{2}{3} \times 0.69[/tex]

[tex]= 0.46 \: mol/ s[/tex]

Therefore, compound f is increasing at the rate of 0.46 mol per second.

To know more about moles refer to the below link:

https://brainly.com/question/26416088

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