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The sum of three consecutive even integers (3 integers in a row) is 120.



Use the following setup and given equation to find your solution:

1st integer = x
2nd integer = x+2
3rd integer = x+4
Equation: x+(x+2)+(x+4)=120




Solve the equation above. What is the largest of the three integers?

Sagot :

Answer:

42

Step-by-step explanation:

x + x + 2 + x + 4 = 120

3x + 6 = 120

3x = 114

x = 114/3

x = 38

38, 40, 42

ShubhamchouhanvrVTidn

The three integers are 38, 40, and 42.

What is an equation?

The equation in mathematics is the relationship between the variables and the number and establishes the relationship between the two or more variables.

Given that the sum of three consecutive even integers (3 integers in a row) is 120. The value of integers will be calculated as below:-

x + x + 2 + x + 4 = 120

3x + 6 = 120

3x = 114

x = 114/3

x = 38

1st integer = x = 38

2nd integer = x+2 = 38 + 2 =  40

3rd integer = x+4 = 38 + 4 = 42

Therefore, the three integers are 38, 40, and 42.

To know more about equations follow

brainly.com/question/14323743

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