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Sagot :
The mass of water will change its temperature is 44.09 g.
Given that the temperature is change by 3.0°C when 635 J of heat is added to it.
Based on the given information, we know the following variables:
ΔT=3°C
Q=635J
C=(4.8 J)/(g×°C)
Here, we want to do is rearrange the equation to solve for m and this can be done by dividing both sides by C and ΔT to get m by itself like this:
m=Q/(ΔT×C)
Now, we want to substitute all the given values in the above formula, we get
m=635J/(3°C×(4.8J/(g×°C)))
m=635J/(14.4J/g)
m=44.09g.
Hence, the mass of water will change its temperature by 3.0 °C when 635 J of heat is added to it 44.09g.
Learn more about temperature from here brainly.com/question/5993190
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