IDNLearn.com is your go-to resource for finding answers to any question you have. Ask your questions and receive comprehensive, trustworthy responses from our dedicated team of experts.
Sagot :
The mass of water will change its temperature is 44.09 g.
Given that the temperature is change by 3.0°C when 635 J of heat is added to it.
Based on the given information, we know the following variables:
ΔT=3°C
Q=635J
C=(4.8 J)/(g×°C)
Here, we want to do is rearrange the equation to solve for m and this can be done by dividing both sides by C and ΔT to get m by itself like this:
m=Q/(ΔT×C)
Now, we want to substitute all the given values in the above formula, we get
m=635J/(3°C×(4.8J/(g×°C)))
m=635J/(14.4J/g)
m=44.09g.
Hence, the mass of water will change its temperature by 3.0 °C when 635 J of heat is added to it 44.09g.
Learn more about temperature from here brainly.com/question/5993190
#SPJ9
Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Thank you for visiting IDNLearn.com. We’re here to provide accurate and reliable answers, so visit us again soon.
