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The sum of 4 consecutive even integers is the same as the least of the integers find the integers

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The four numbers are: -4, -2 ,0, 2 Answer.

How do you solve this: the sum of four consecutive even integers is equal to least of the integer

Solution: Let the numbers be n, n+2, n+4 and n+6.

Their sum = 4n+12 = n or

3n+12 = , or

3n = -12,

n= -4

therefore we get -4, -2, 0, 2

The four numbers are: -4, -2 ,0, 2 . Answer.

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