The differentiation of the given function is expressed as; 2x - √3(y) = 0
How to carry out Differentiation?
We want to differentiate the function;
x² - √3(xy) + 2y² = 12
To differentiate this means to express as;
x²(dy/dx) - √3(xy)(dy/dx) + 2y²(dy/dx) = 12(dy/dx)
This gives us;
2x - √3(y) + 0 = 0
2x - √3(y) = 0
Thus, the differentiation of the given function is expressed as;
2x - √3(y) = 0
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