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The hole having the diameters likely between 4.048 and 4.0553 is 17.
Maximum value of diameter = 4.05 + 0.0028 = 4.0528
Minimum value of diameter = 4.05 - 0.0028 = 4.0472
So, the diameters of the holes are in AP with common difference
= (2 × 0.0028) / 20 = 0.00028
So, the AP is:
4.0472, 4.04748, 4.04776, 4.04804, …, 0.0.0528
So, the first 3 terms are not included between 4.048 and 4.0553
Hence, the answer is 20 - 3 = 17
Therefore, the hole having the diameters likely between 4.048 and 4.0553 is 17.
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