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Sagot :
The molarity of the solution is 0.528 mol/L.
Given,
Molarity = 0.0480 LiF.
Density = 1.10 g/ml
0.0480 moles of LiF are present in 1 kg of solvent.
Mass of 0.0480 moles of LiF = 0.0480 mol × 26 g/mol = 1.248 g
Mass of the solution (m)= 1 kg (solvent) + 1.248 g(solute)
m = 1000 g + 1.248 g = 1001.248 g
Finding the volume of the solution,
Volume = Mass / density
Putting the values of mass and density, we get the volume,
Volume = 910.2254 mL or, 0.9102254 L
The molarity of the solution is the moles of the compound in one liter of solutions.
Molarity = mass of compound/ molar mass × volume(L)
By putting the values we get,
Molarity = 0.528 mol/L
Hence the molarity of the solution is 0.528 molar.
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