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Sagot :
The volume of oxygen required at STP is 7 L.
STP is a pressure of 100 kPa and a temperature of 273.15 K. Or, 1 mole of any ideal gas occupies 22.7 L at STP.
Therefore, we need to find out the number of moles of oxygen required in the reaction.
Using the molar mass of water,
10.5 g × 1 mole of water/ 18.02 g = 0.577 moles of water.
1: 2 is the ratio between oxygen and water in a water molecule, which means 1 mole of oxygen produces 2 moles of water.
0.577 moles of H₂O × 1 mole O₂ / 2 moles of H₂O = 0.2885 moles O₂.
So, if 22.7 L at STP is occupied by 1 mole, then
0.2885 × 22.7 L / 1 mole = 6.548 L
Rounded to the nearest whole number, we get 7 L.
Hence, the volume of oxygen at STP is 7L.
To learn more about volume and STP, visit: https://brainly.com/question/15469566
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