Anahi3477idn
Answered

IDNLearn.com: Your destination for reliable and timely answers to any question. Join our interactive community and get comprehensive, reliable answers to all your questions.

What is the line of symmetry for the parabola whose equation is y=x²-12x + 7?
Ox=12
Ox=6
Ox=-6

Sagot :

Fieryanswererftidn

Answer:

x = 6

Explanation:

completing square:

[tex]y=x^2-12x+7[/tex]

[tex]y=(x^2-12x)+7[/tex]

[tex]y=(x-6)^2+7-(-6)^2[/tex]

[tex]y=(x-6)^2+7-36[/tex]

[tex]y=(x-6)^2-29[/tex]

Comparing with quadratic equation [tex]y=ax^2 + bx+c[/tex], in vertex form where [tex]y = a(x-h)^2+k[/tex]. In this x - h = 0, x = h defines the symmetry of equation.

So here the symmetry for parabola:

x - 6 = 0

x = 6

Semsee45idn

Answer:

x = 6

Step-by-step explanation:

The axis of symmetry of a parabola is the x-value of its vertex.

For a quadratic function in the form  [tex]y=ax^2+bx+c[/tex], the x-value of the vertex is:

[tex]x=-\dfrac{b}{2a}[/tex]

Given function:

[tex]y=x^2-12x+7[/tex]

Therefore:

[tex]a=1, \quad b=-12, \quad c=7[/tex]

So the axis of symmetry of the given quadratic function is:

[tex]\implies x=-\dfrac{b}{2a}=-\dfrac{-12}{2(1)}=\dfrac{12}{2}=6[/tex]

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find precise solutions at IDNLearn.com. Thank you for trusting us with your queries, and we hope to see you again.