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Sagot :
y - 11 = -3 ( x + 2) is the equation in point-slope form of the line .
What is slope ?
- The inclination of a line with respect to the horizontal is measured numerically.
- The ratio of the vertical to the horizontal distance between any two points on a line, ray, or line segment is known as its slope in analytic geometry ("slope equals rise over run").
Given points : (0, 5) and (−2, 11)
Slope of the line passing through given points
[tex]m = \frac{y_{2}- y_{1} }{x_{2} - x_{1} } = \frac{11 - 5}{-2 - 0} = \frac{6}{-3} = -3[/tex]
Thus, slope of line passing through given points m=-3
We know that the equation of a line passing through points ( x₀ , y₀) with slope 'm' is ( y - y₀ ) = m(x - x₀)
Thus, equation of a line passing through (−2, 11) with slope m=-3 will be
( y - 11 ) = -3 ( x - (-2))
y - 11 = -3 ( x + 2)
Hence, the equation of line is y - 11 = -3 ( x + 2).
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