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how much water must be evaporated from 500 grams of a 10% salt solution to obtain a 15% salt solution?

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The amount of water that must be evaporate from 500 grams of a 10% salt solution to obtain a 15% salt solution is: 166.67 g

To solve this problem, the formula and the procedure that we have to use is:

c1 * m1 = c2 * m2

Where:

  • c1= concentration of the concentrated solution
  • m1 = mass of the concentrated solution
  • c2 = concentration of the diluted solution
  • m2 = mass of the diluted solution

Information about the problem:

  • c1 = 10%
  • m1=500 g
  • c2 = 15%
  • m2= m1 - x
  • Amount of water evaporate = x

Applying the dissolution of concentrations formula, we get:

c1 * m1 = c2 * m2

10% * 500g = 15% * (500 g - x)

0.10 * 500g = 0.15*(500g - x)

50 g = 75g - 0.15x

Isolating the (x) variable, we have:

0.15x = 75g - 50 g

0.15x = 25g

x = 25g / 0.15

x = 166.67 g

What is a solution?

In chemistry a solution is known as a homogeneous mixture of two or more components called:

  • Solvent: it usually is in a major amount than the solute
  • Solute: it usually is in less amount than the solvent

Learn more about chemical solution at: brainly.com/question/13182946

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