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Sagot :
The values of f(0) that can be read from (a similar question in part (a) and (c)) the table, functions, and graph in the question are;
(a) f(0) = 1
(b) f(0) = 12
(c) f(0) = -2
How can the table, function, and graph be evaluated to find f(0)?
Part of the question appears missing. From a similar question online, we have;
(a) A table of values;
x: -1, 0, 1, 2, 3
y: 7, 1, 6, -3, -4
Taking the function, f(x) = y, we have;
From the above values in the table, when x = 0, y = f(0) = 1
Therefore;
- f(0) = 1
(b) y = 12 - 2•x²
Taking the function, f(x) = y, we have;
At x = 0, y = f(0) = 12 - 2 × 0² = 12
Therefore;
- f(0) = 12
(c) A graph of a parabola passing through the points (-1, 3), (2, -6), (5, 3)
Let f(x) = a•x² + b•x + c, represent the function, we have;
f(-1) = 3 = a•(-1)² + b•(-1) + c = a - b + c
- 3 = a - b + c...(1)
f(2) = -6 = a•(2)² + b•(2) + c = 4•a + 2•b + c
- -6 = 4•a + 2•b + c...(2)
f(5) = 3 = a•(5)² + b•(5) + c = 25•a + 5•b + c
- 3 = 25•a + 5•b + c...(3)
Solving the system of linear equations, (1), (2), (3) using a graphing calculator gives;
a = 1, b = -4, c = -2
Which gives;
f(x) = x² - 4•x - 2
Therefore;
f(0) = 0² + 4×0 - 2 = -2
Which gives;
- f(0) = -2
Learn more about evaluation of functions here:
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